姝e湪瀹屽杽浠ヤ笅鍐呭椤甸潰锛岃鑰愬績绛夊緟
$age = strtotime(substr($
id
, 6, 8) . ' +' . $diff . 'years') > $today ? ($diff + 1) : $diff; return $age; } 本文来源:https://
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...